1 Answer

Russell Dias · Answer 1 · 2021-06-09T12:59:10+0000

Complete Question

An object floats in water with 5/8 of its volume submerged. The ratio of the density of the object to that of water is:

(a) 8/5

(b) 1/2

(c) 3/8

(d) 5/8

(e) 2/1

Answer:

The correct option is d

Step-by-step explanation:

From the question we are told that

The ratio of the volume of the object submerged to the total volume of the object is
(V_w)/(V_o) = (5)/(8)

Generally the buoyancy force acting on the object is equal to the weight of the water displaced and this is mathematically represented as

F_b = W

Now the mass of the water displaced is mathematically represented as

$m_w = \rho_w * V_w$

While the mass of the object is mathematically represented as

$m_o = \rho_o * V_o$

So

$F_b = W \ \equiv \ \rho * V_o * g = \rho * V_w * g$

=>
$(V_w)/(V_o) = (\rho_o)/(\rho_w)$

From the question that it volume of the water displace (equivalent to the volume of the object in water ) to the volume of the total object is

(V_w)/(V_o) = (5)/(8)

So

$(\rho_o)/(\rho_w) = (5)/(8)$

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