Question

X & y intercept for 4x+6y=12

Answer 1

x- intercept at (3, 0)

y- intercept at (0, 2)

Explanation:

x-intercept occurs at y=0.

4x +6y= 12

when y=0,

4x +6(0)= 12

4x= 12

x= 12 ÷4

x= 3

Thus, x-intercept occurs at x=3, at the point (3, 0).

y- intercept occurs at x=0.

4x +6y= 12

when x=0,

4(0) +6y= 12

6y= 12

y= 12 ÷6

y= 2

Thus, y- intercept occurs at the point (0, 2).