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What is an equation of the line that passes through the point (-2, -3) and is

parallel to the line 5x + 2y = 14?

1 Answer

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Answer: 2y + 5x + 16 = 0

Explanation:

To solve this you need to understand the principle/ conditions for parallelism and perpendicularity.

for two lines to be parallel to each other, their gradients or slopes (m) must be equal, that is m₁ = m₂

Now from the given equation,

5x + 2y = 14 , we need to rearrange it to conform to the equation of a straight line so that the gradient could be established. ie

y = mx + c where m is the gradient

2y = -5x + 14

y = -5x/2 + 14/2

y = ⁻⁵ˣ/₂ + 7 , therefore , m₁ = ⁻⁵/₂ and m₂ = ⁻⁵/₂ ( parallelism Rule )

The next step is to find the value of C using the coordinate ( -2, -3 )

-3 = ⁻⁵/₂ ˣ ⁻² + C,

-3 = ¹⁰/₂ + C

-3 = 5 + C

C = -8.

Now to find the equation of the line that passed through the coordinate

y = mx + c

y = ⁻⁵ˣ/₂ - 8

2y = -5x - 16

2y + 5x + 16 = 0.

User Alex Pereira
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