Question

Find the angle between two polarizers that will result in one-eighth of the light incident on the second polarizer passing through.

Answer 1

The angle is
`\theta = 6.93 *10^(1)`

Step-by-step explanation:

From the question we are told that

The intensity of light emerging from the second polarizer is
`I_2 = (1)/(8) * I_1`

Now the light emerging from the first polarizer is
`I_1 = (I_o)/(2)`

Where
`I_o` is the intensity of the unpolarized light

Now according to Malus law the intensity of light emerging from the second polarizer is mathematically represented as

`I_2 = (I_1)/(8) = I_1 cos^2(\theta )`

=>
`I_2 = (I_1)/(8) = I_1 cos^2(\theta )`

=>
`\theta = cos^(-1)[0.3536]`

=>
`\theta = 69.3^o`

=>
`\theta = 6.93 *10^(1)`