Answer:
36km/h
Step-by-step explanation:
since the acceleration of the train was 0.5m/s² i.e it is constant . since the acceleration is constant you can use one of the "SUVAT" equations to find the answer.
the equation that best fits this question is: v²=u² + 2āS.
v stands for final velocity
u stands for intial velocity
v²=u² + 2āS since the car started from rest the intial velocity is zero.
v²=u² + 2āS
v²= 0 + 2(0.5m/s²)*100m
v²= 1m/s²*100m
√v²=√100m²/s²
v=10m/s
1km/hr = 1/3.6m/s
x. = 10m/s.
use criss cross method to find the value of x
x=( 1km/hr* 10m/s)
1/3.6m/s
x= 36km/hr