Answer:
Bridget's first fish =f = 5 ounces
Bridget's dad first fish weighs 17 ounces
Explanation:
Bridget went fishing with her dad. Bridget caught the first fish of the day, and it weighed f ounces. That day, she caught four more fish. One was 2 times the weight of the first fish, another was 2 more than 3 times the weight of the first fish, the next was 1/2 the weight of the first fish, and the last was 3/5 the weight of the first fish. Bridget’s dad caught four fish. The first fish he caught weighed 2 more than 3 times the weight of the first fish caught that day. One fish weighed 4/5 the weight of the first fish caught that day, one weighed 4 more than 2 times the weight of the first fish caught that day, and the last weighed 1/2 the weight of the first fish caught that day. If all the fish Bridget caught have the same total weight as all the fish her dad caught, then the first fish Bridget caught weighed___ ounces and the first fish her dad caught___ weighed ounces.
Solution:
Bridget's fishes:
f ounces
2f ounces
3f+2 ounces
1/2f ounces
3/5f ounces
Total= f +2f + (3f+2) + 1/2f +3/5f
=3f + 3f + 2 + 5f+6f/10
=6f + 2 + 11f/10
=60f+11f/10 +2
=71/10f +2
Bridget's dad fishes
3f+2
4/5f
2f+4
1/2f
Total =(3f+2) + (2f+4) + 4/5f +1/2f
=3f+2+2f+4 + 8f+5f/10
=5f + 6 + 13/10f
= 50f+13f/10 + 6
=63/10f +6
Equate the total weight
71/10f +2=63/10f +6
Collect like terms
71/10f - 63/10f =6-2
71f-63f/10 = 4
8f/10=4
Cross product
8f=40
Divide both sides by 8
f=5
Bridget's first fish =f = 5 ounces
Bridget's dad first fish = 3f +2
=3(5)+2
=15+2
=17 ounces
Bridget's dad first fish weighs 17 ounces