Question

Find the solution set for this equation M^2-4=0

Answer 1

Explanation:

Hey, there !!

Let's simply work with it,...................

Here, theequation is,

`{m }^(2) - 4 = 0`

`or \: {m }^(2) = 4`

`or \: m = + - √(4)`

`or \: m = + - \sqrt{ {2}^(2) }`

cancelling square and square root we get answer is,

= (+ - 2).

It means the value of m is plus(+) minus(-) 2.

Hope it helps...