Question

certain atom has 86 protons. Assume that the nucleus is a sphere with radius 6.98 fm and with the charge of the protons uniformly spread through the sphere. At the nucleus surface what are (a) the magnitude and (b) direction (radially inward or outward) of the electric field produced by the protons?

Answer 1

a.
`2.54 * 10^(21) NC^(-1)`

b. Outwards

Step-by-step explanation:

The computation is shown below:

a. The magnitude could be computed by applying the following formula

Electric field, E is

`= (kq)/(r^(2)) \\\\ = (9*10^(9) *86*1.6*10^(-19))/((6.98*10^(-15))^2)`

`= 2.54 * 10^(21) NC^(-1)`

b. As we can see that there is a positive charge so the direction would be in the outward direction in the electric field i.e. produced by the protons

Basically we applied the above formula for the first part