If the spring constant is 10 N/m and the spring is stretched 1 m, what is the Force?

asked Jul 7, 2021 233k views

1 vote

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4 votes

Answer:

10N

Step-by-step explanation:

Applying the Hooke law:

F = kx

F: Force

k: stiffness coefficient

x: stretched distance

F = 10N/m x 1m = 10N

Haxwithaxe answered Jul 12, 2021

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