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Find the area of a rhombus with a 120 degree angle and sides 10 cm

1 Answer

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Answer:

A = 50√3 cm²

Explanation:


A=s^2\cdot \sin\alpha\\\\s=10\\\alpha=120^o\\\\A=10^2\cdot\sin(120^o)=100\sin(180^o-60^o)=100\sin(60^o)=100\cdot\frac{\sqrt3}2=50\sqrt3

User LeWoody
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