Answer:
Explanation:
Given
2^x [(x+1)³ -1] = 2^x - (x+1)³ + 1
Lep p = 2^x, and q = (x+1)³ - 1
Then the original equation becomes
pq = p - q
p - q - pq = 0
p(1 - q) - q = 0
p = q/(1 - q)
2^x = [(x+1)³ - 1]/[-(x+1)³]
2^x = [1 - (x+1)³]/[(x+1)³]
2^x = (x+1)^(-3) - 1