Answer:
Explanation:
AB ≅ BC. So, ΔABC is an isosceles triangle
Opposite angles of equal sides are equal.
∠BAC = ∠BCA = x°
In ΔABC,
∠ABC + ∠BAC + ∠BCA = 180 {Angle sum property of triangle}
56 + x + x = 180
56 + 2x = 180
2x = 180 - 56
2x = 124
x = 124/2
x = 62°
∠BAC = ∠BCA = 62°
∠DCF = ∠BCA {Vertically opposite angles}
∠DCF = 62°
CDEF is a parallelogram.
In parallelogram, opposite angles are congruent.
∠DEF = ∠DCF
∠DEF = 62°
In a parallelogram, sum of adjacent angles = 180
∠DEF + ∠CDE = 180
62 + ∠CDE = 180
∠CDE = 180 - 62
∠CDE = 118°
∠CFE = ∠CDE {In parallelogram, opposite angles are congruent}
∠CFE = 118°