Answer:
Thus, the change of flux linkage is 30 Wb.
Step-by-step explanation:
Given, mutual inductance of coil
M= 1.5 H
Current change in coil dI=20-0=20A
Time taken in change dt=0.5s
Induced emf in the coil
e=MdIdt=dϕdtor,dϕ=M.dI=1.5×20dϕ=30Wb
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