Question

In a two-slit experiment, the slit separation is 3.34 ⋅ 10 − 5 m. The interference pattern is created on a screen that is 3.30 m away from the slits. If the 7th bright fringe on the screen is 29.0 cm away from the central fringe, what is the wavelength of the light?

Answer 1

The wavelength is
`\lambda = 419 \ nm`

Step-by-step explanation:

From the question we are told that

The distance of separation is
`d = 3.34 *10^(-5) \ m`

The distance of the screen is
`D = 3.30 \ m`

The order of the fringe is n = 7

The distance of separation of fringes is y = 29.0 cm = 0.29 m

Generally the wavelength of the light is mathematically represented as

`\lambda = (y * d )/( n * D)`

substituting values

`\lambda = (0.29 * 3.34*10^(-5) )/( 7 * 3.30)`

`\lambda = 4.19*10^(-7)\ m`

`\lambda = 419 \ nm`