Question

If the data rate is 10 Mbps and the token is 64 bytes long (the 10-Mbps Ethernet minimum packet size), what is the average wait to receive the token on an idle network with 40 stations? (The average number of stations the token must pass through is 40/2 = 20.) Ignore the propagation delay and the gap Ethernet requires between packets.

Answer 1

1.024x10^-5

Step-by-step explanation:

To calculate the transmission delay bytes for the token,

we have the token to be = 64bytes and 10mbps rate.

The transmission delay = 64bytes/10mbps

= 51.2 microseconds

A microsecond is a millionth of a second.

= 5.12 x 10^-5

The question says the average number of stations that the token will pass through is 20. Remember this value is gotten from 40/2

20 x 5.12 x 10^-5

= 0.001024

= 1.024x10^-5

Therefore on an idle network with 40 stations, the average wait is

= 1.024x10^-5