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How does f(x) = 3x - 8 change over the interval from x = 5 to x = 6?

User Fingerman
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I realise you've probably gotten past this question, but I'm throwing it out for all future askers of this question ¯\_(ツ)_/¯

C) ƒ(x) increases by a factor of 3

ƒ(x) increases by a factor of 3

f(4) = 3^4

f(5) = 3^5

f(5) /f(4) = 3^5 /3^4 = 3^5−4 = 3^1 = 3

The value of ƒ(x) changes from 81 to 243 over the interval from x = 4 to x = 5.

This is an increase by a factor of 3.

User Kopiczko
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