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The vertex formation of a parabola is x = 8(y- 1)2-76.

What is the standard form of the equation?

User Lbatson
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2 Answers

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The answer to this question is x = 8y^2 - 16y -68
User Jesse De Wit
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Answer:


\boxed{x=8y^2-16y-68}

Explanation:

Hello, please consider the following.


x=8(y- 1)^2-76\\\\x=8(y^2-2y+1)-76\\\\x=8y^2-16y+8-76\\\\\boxed{x=8y^2-16y-68}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

User Strongopinions
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