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Time spent using e-mail per session is normally distributed with a mean = to 8 minutes and standard deviation = 2minutes. If a random samples of 36 sessions were selected, the computed sample standard deviation would be

a. 0.25
b. 0.3333
c. 0.42
d. 0.48

User Coxley
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1 Answer

1 vote

Answer:

The correct option is (b) 0.3333.

Explanation:

The standard deviation of the sampling distribution of sample mean
(\bar x) is known as the standard error
(\sigma_(\bar x)).

The standard error is given as follows:


\sigma_(\bar x)=(\sigma)/(√(n))

The information provided is:


\mu=8\\\\\sigma=2\\\\n=36

Compute the standard deviation of the sample mean as follows:


\sigma_(\bar x)=(\sigma)/(√(n))


=(2)/(√(36))\\\\=(2)/(6)\\\\=(1)/(3)\\\\=0.3333

Thus, the standard deviation of the sample mean is 0.3333.

User Priyankchoudhary
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