Question

Find an equation of the line: Through the point (2, −4) with a y-intercept of −2 Through the points (4,2) and (3,1) Through the point (3,2) with a slope of −2

Answer 1

Answer and Step-by-step explanation: Equations of line through points and slope can be determined by:

`y-y_(0)=m(x-x_(0))`

m is slope

• Point (2,-4) and y-intercept = -2

Y-intercept is point (0,-2)

m =
`(y_(a)-y_(b))/(x_(a)-x_(b))`

m =
`(-4-(-2))/(2-0)`

m = - 1

Equation:

`y+2=-1(x-0)`

`y=-x-2`

• Points (4,2) and (3,1)

m =
`(2-1)/(4-3)`

m = 1

Equation:

`y-2=(x-4)`

`y=x-2`

• Point (3,2) and slope = -2

m = -2

Equation:

`y-2=-2(x-3)`

`y=-2x+6+2`

`y=-2x+8`