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A spray irrigation system waters a section of a farmer's field. If the water shoots a distance of 85 feet, what is the area that is watered as the sprinkler rotates through an angle of 60 degrees? Use 3.14 for pi . Round your answer to the nearest square foot, and enter the number only.

User Jerrold
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2 Answers

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Answer:176

Explanation:

6 times 29.33333333333333

User Aliopi
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6 votes

Answer:

The watered area is approximately 3783 square feet.

Explanation:

The area that is watered due to the rotation of the spankler is a circular section area (
A), whose formula is:


A = (\theta )/(2)* (1)/(360^(\circ))* 2\pi * d^(2)

Where:


d - Water distance, measured in feet.


\theta - Rotation angle, measured in sexagesimal degrees.

Given that
d = 85\,ft and
\theta = 60^(\circ), the watered area is:


A = (60^(\circ))/(2) * (1)/(360^(\circ))* 2\pi * (85\,ft)^(2)


A \approx 3783\,ft^(2)

The watered area is approximately 3783 square feet.

User MrKodx
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