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Determine the length ofx and the length ofy, to the nearest tenth of a metre.

12
Х
37°
a. x = 7.2 m and y= 9.7 m
b. x = 9.6 m and y = 12.9 m
42°
x = 9.6 m and y= 14.3 m
d. x = 7.2 m and y = 10.8 m
c.

Determine the length ofx and the length ofy, to the nearest tenth of a metre. 12 Х-example-1
User BobB
by
5.4k points

1 Answer

2 votes

Answer:

Option D. x = 7.2 m and y = 10.8 m.

Explanation:

A. Determination of the value of x

Angle θ = 37°

Opposite = x

Hypothenus = 12 m

Using the sine ratio, the value of x can be obtained as follow:

Sine θ = Opposite /Hypothenus

Sine 37 = x/12

Cross multiply

x = 12 × Sine 37

x = 7.2 m

B. Determination of the value of y.

Angle θ = 42°

Opposite = x = 7.2 m

Hypothenus = y

Using the sine ratio, the value of y can be obtained as follow:

Sine θ = Opposite /Hypothenus

Sine 42 = 7.2/y

Cross multiply

y × Sine 42 = 7.2

Divide both side by Sine 42

y = 7.2 / Sine 42

y = 10.8 m

Therefore, x = 7.2 m and y = 10.8 m

User SaturnFromTitan
by
5.5k points
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