Answer:
Here are some examples
Step-by-step explanation:
NaCl
Cation = Na⁺, Anion = Cl⁻; ΔEN = |0.93 - 3.16| = 2.23
MgS
Cation = Mg²⁺, Anion = O²⁻; ΔEN = |1.31 - 3.44| = 2.53
KBr
Cation = K⁺, Anion = Br⁻; ΔEN = |0.82 - 2.96| = 2.14
CaF₂
Cation = Ca²⁺, Anion = F⁻; ΔEN = |1.00 - 3.98| = 2.98
In each case, ΔEN > 1.6, so the compound is ionic.