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The formula of complex ion formed when aluminum hydroxide dissolves in sodium hydroxide will be: Select the correct answer below: [AlOH]2+

User Teemo
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Answer:

Al(OH)₃ + OH⁻ → Al(OH)₄⁻

The compound is called hydroxoaluminate.

Step-by-step explanation:

Aluminiun Hydroxide → Al(OH)₃

NaOH → Sodium hydroxide.

The Al(OH)₃ is an amphoteric compound, while the NaOH is a strong base. When they react, we may think that, fist of all, the base can dissociate: NaOH → Na⁺ + OH⁻

So the Al(OH)₃ will be a Lewis acid, as it can donate a pair of e⁻

Al(OH)₃ + OH⁻ → Al(OH)₄⁻

User Imbrizi
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