Answer:

Explanation:
will form a sequence as,
499, 498, 497.......7 terms
Since there is a common difference between successive and previous term,
d = 498 - 499 = -1
This sequence is an arithmetic sequence.
Sum of n terms of an arithmetic sequence is,
![S_(n)=(n)/(2)[2a+(n-1)d]](https://img.qammunity.org/2021/formulas/mathematics/college/pxwtsxrkkgvi8x38vv0qpvwpbj0uqydi2i.png)
where a = first term of the sequence
n = number of term
d = common difference
For the given given sequence,
![S_(7)=(7)/(2)[2(499)+(7-1)(-1)]](https://img.qammunity.org/2021/formulas/mathematics/college/twcp6sxzckdtpn0dvwxue5ozddae0pa6qx.png)
=
![(7)/(2)[998-6]](https://img.qammunity.org/2021/formulas/mathematics/college/2uobd4o2ilw2577uiy09yu4ghlc9uyd4uh.png)
=

= 3472
Therefore, sum of seven terms of the given sequence will be 3472.