Answer:
When x = 2, y = 4, and z = 0, 3x + 4z - 2 + 3y = 16.
Explanation:
3x + 4z - 2 + 3y
Substitute given values x = 2, y = 4, and z = 0.
3(2) + 4(0) - 2 + 3(4)
Multiply 3 and 2.
6 + 4(0) - 2 + 3(4)
Multiply 4 and 0.
6 - 2 + 3(4)
Multiply 3 and 4.
6 - 2 + 12
Subtract 2 from 6.
4 + 12
Add 4 and 12.
16