Answer:
0.9938
Explanation:
We can find this probability using a test statistic.
The test statistic to use is the z-scores
Mathematically;
z-score = (x-mean)/SD/√n
from the question, x = 119 , mean = 117 , SD = 6.4 and n = 64
Plugging these values in the z-score equation above, we have;
z-score = (119-117)/6.4/√64
z-score = 2/6.4/8
z-score = 2.5
The probability we want to find is;
P(z < 2.5)
we can get this value from the standard normal distribution table
Thus; P(z < 2.5) = 0.99379
Which to four decimal places = 0.9938