Question

A chemist prepares a solution of silver(I) nitrate(AgNO3) by measuring out 269. mu mol of silver(I) nitrate into a 300. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mmol/L of the chemist's silver(I) nitrate solution.

Answer 1

concentration in mmol/L = 8.97 × 10⁻¹ mmol/L

Step-by-step explanation:

Given that:

the number of moles of silver(I) nitrate(AgNO3) the chemist used in preparing a solution = 269 mmol = 269 × 10⁻³ mmol

The volume of the volumetric flask = 300 mL = 300 × 10⁻³ L

In order to calculate the concentration in mmol/L of the chemist's silver(I) nitrate (AgNO3) solution , we used the formula which can be expressed as;

`concentration \ in \ mmol/L = ( number \ of \ mmol)/(vol. \ of \ the \ solution)`

`concentration \ in \ mmol/L = ( 269 * 10^(-3 ) \ mmol )/(300 * 10^(-3) \ L )`

concentration in mmol/L = 0.8966 mmol/L

concentration in mmol/L = 8.97 × 10⁻¹ mmol/L