Question

16. The concentration of a solution of potassium hydroxide is determined by titration with nitric

acid. A 30.0 mL sample of KOH is neutralized by 42.7 mL of 0.498 M HNO3. What is the
concentration of the potassium hydroxide solution?

Answer 1

`M_(base)=0.709M`

Step-by-step explanation:

Hello,

In this case, since the reaction between potassium hydroxide and nitric acid is:

`KOH+HNO_3\rightarrow KNO_3+H_2O`

We can see a 1:1 mole ratio between the acid and base, therefore, for the titration analysis, we find the following equality at the equivalence point:

`n_(acid)=n_(base)`

That in terms of molarities and volumes is:

`M_(acid)V_(acid)=M_(base)V_(base)`

Thus, solving the molarity of the base (KOH), we obtain:

`M_(base)=(M_(acid)V_(acid))/(V_(base)) =(0.498M*42.7mL)/(30.0mL)\\ \\M_(base)=0.709M`

Regards.