Answer:
Option A Center: 2,-3 radius =5
Explanation:
![(x-h) ^2+(y-k) ^2 =r^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/82dddezpk9z7zqet24n8zjy620myu2yqo5.png)
The above equation is the general standard equation for the circle centered at (h,k) with radius r
Given that the equation of the circle is
![(x-2) ^2+(y+3) ^2 =25](https://img.qammunity.org/2021/formulas/mathematics/high-school/zgtp4s3463os6jh205k2010hl3f08xabmz.png)
Comparing this with the general equation we can get the center and the radius as
![(x-h) ^2+(y-k) ^2 =r^2\\(x-(2)) ^2+(y-(-3)) ^2 =5^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/h98np4pzcb208s9xvh0i3els69137n2j1i.png)
We can now see that
h= 2
k= -3 and
r= 5