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Need help please! what is the total length of a 20 mm steel coiled like a spring with a 16 turns and an outer diameter of 600 mm. pitch is 300 mm. Show your solution please coz i don't really know how to do it! thanks

User Gooseman
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1 Answer

1 vote

Answer:

L = 29,550 mm

Explanation:

i think i've done this before.. but anyway Lets make it simple and easy.

Let A = 600mm

Let B = 300mm

Let C = 16 as number turns

Let d = 20mm

L = sqrt ((3.14 * (600 - 20))² + 300³) * 16

L = 29,550 mm

User Eliah Kagan
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