Question

A wire of length 5mm and Diameter 2m extends by 0.25 when a force of 50N was use. calculate the

a. Stress of the wire.
b. Strain of the wire​

Answer 1

Answer and Explanation:

Data provided in the question

Force = 50N

Length = 5mm

diameter = 2.0m =
`2* 10^(-3)`

Extended by = 0.25mm =
`0.25* 10^(-3)`

Based on the above information, the calculation is as follows

a. The Stress of the wire is

`= (force\ applied)/(area\ of \ circle)`

here area of circle = perpendicular to the are i.e cross-sectional i.e

=
`(\pi d^(2))/(4)`

=
`(\pi(2* 10^(-3))^2)/(4)`

Now place these above values to the above formula

`= (4* 50)/(\pi* 4 * 10^(-6)) \\\\ = (50)/(\pi)`

= 15.92 MPa

As 1Pa = 1 by N m^2

So,

MPa = 10^6 N m^2

b. Now the strain of the wire is

`= (Change\ in\ length)/(initial\ length) \\\\ = (0.25* 10^(-3))/(5)`

=
`5 * 10^(-5)`