Question

Help please!!! Thank you

Answer 1

Option (G)

Explanation:

Let the length of the race = a miles

Since, Speed =
`\frac{\text{Distance}}{\text{Time}}`

Time taken to cover 'a' miles with the speed = 12 mph,

Time taken '
`t_1`' =
`(a)/(12)`

Time taken to cover 'a' miles with the speed = 11 mph,

Time taken '
`t_2`' =
`(a)/(11)`

Since the time taken by David to cover 'a' miles was 10 minutes Or
`(1)/(6)` hours more than the time he expected.

So,
`t_2=t_1+(1)/(6)`

`(a)/(11)=(a)/(12)+(1)/(6)`

`(a)/(11)-(a)/(12)=(1)/(6)`

`(12a-11a)/(132)=(1)/(6)`

a = 22 mi

Therefore, distance of the race = 22 mi

Option (G) is the correct option.