Answer:
x=12
Explanation:
To solve for the variable, we must isolate the variable, which is x.
![√(x+4) -3=1](https://img.qammunity.org/2021/formulas/mathematics/high-school/ft6zm6v9ku6cjq3yivvrop2whduvt3h8d7.png)
3 is being subtracted from the square root of x+4. The inverse of subtraction is addition. Add 3 to both sides of the equation.
![√(x+4) -3+3=1+3](https://img.qammunity.org/2021/formulas/mathematics/high-school/2g6fkrcncetkrf6d5aeee3wgka1y8vyr6n.png)
![√(x+4) =1+3](https://img.qammunity.org/2021/formulas/mathematics/high-school/ghndlar0579xbm0h31jfm9rd8zfcmma6jg.png)
![√(x+4) =4](https://img.qammunity.org/2021/formulas/mathematics/high-school/eas06389uhn5qd7dj2uh3u0222u4mlus9f.png)
The square root of x+4 is being taken. The inverse of a square root is a square. Square both sides of the equation.
![(√(x+4))^2 =4^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/3d7y83yrwglza0lnouq33mv627lxk4lv5h.png)
![x+4=4^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/axdtf2nj4qllw4ott6owdfjbveh6xptcmr.png)
Evaluate the exponent.
4^2= 4*4=16
![x+4=16](https://img.qammunity.org/2021/formulas/mathematics/high-school/2an4hvv0zjo0qv72ctdakgdo11p6ln64sz.png)
4 is being added to x. The inverse of addition is subtraction. Subtract 4 from both sides of the equation.
![x+4-4=16-4](https://img.qammunity.org/2021/formulas/mathematics/high-school/jeqbpnyi477ickdzan7xcn9veg74ld04jv.png)
![x=16-4](https://img.qammunity.org/2021/formulas/mathematics/high-school/p8p8m2gwp3pb0o52dl9lu7i2pagv0jk4md.png)
![x=12](https://img.qammunity.org/2021/formulas/mathematics/middle-school/kzh72we7ptn8hlgavxhsl5e208kjtiramm.png)
The solution to this equation is x=12.