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What is the true solution to the equation below? 2 in e in2×-in e in 10×= in 30 A x=30 B x=75 C x=150 D x=300

2 Answers

4 votes

Answer:

b x=75

Explanation:

User Tim Martens
by
4.5k points
5 votes

Answer:

Option B.

Explanation:

Let as consider the given equation:


2\ln e^(\ln 2x)-\ln e^(\ln 10x)=\ln 30

It can be written as


2(\ln 2x)-(\ln 10x)=\ln 30
[\because \ln e^a=a]


\ln (2x)^2-(\ln 10x)=\ln 30
[\because \ln a^b=b\ln a]


\ln (4x^2)/(10x)=\ln 30
[\because \ln (a)/(b)=\ln a-\ln b]


\ln (2x)/(5)=\ln 30

On comparing both sides, we get


(2x)/(5)=30

Multiply both sides by 5.


2x=150

Divide both sides by 2.


x=75

Therefore, the correct option is B.

User Vinay S Shenoy
by
5.2k points