Question

The people who responded to a survey reported that they had either brown, green, blue, or hazel eyes. The results of the survey are shown in the table. A 2-column table has 4 rows. The first column is labeled Eye Color with entries brown, green, blue, hazel. The second column is labeled Number of People with entries 20, 6, 17, 7. What is the probability that a person chosen at random from this group has brown or green eyes? StartFraction 3 Over 25 EndFraction StartFraction 7 Over 25 EndFraction StartFraction 13 Over 25 EndFraction StartFraction 17 Over 25 EndFraction

Answer 1

13/25

Explanation:

Total number of people = 50

Probability of choosing a person with brown eyes [P(A)] = 20/50

Probability of choosing a person with green eyes [P(B)] = 6/50

Using the addition rule of mutual exclusive events (since they have specified brown OR blue, we use this formula):

P(A U B) = P(A) + P(B)

=> P(A U B) = 20/50 + 6/50 = 26/50 = 13/25

Therefore the probability of a person choosing a group that has brown or green eyes = 13/25

Also I got it right on edge haha, if you're still worried!!!!!!!!

Hope this helps :))))))))))))))

Answer 2

`P(Brown\ or\ Green) = (13)/(25)`

Explanation:

Given

`n(Brown) = 20`

`n(Green) = 6`

`n(Blue) = 17`

`n(Hazel) = 7`

Required

Determine the probability of Brown or Green eyes

First, the total number of respondents have to be calculated;

`Total = 20 + 6 + 7 + 17`

`Total = 50`

The events described above is a mutually exclusive event and as such, the required probability will be calculated by;

`P(Brown\ or\ Green) = P(Brown) + P(Green)`

Calculating P(Brown)

`P(Brown) = (n(Brown))/(Total)`

Substitute 20 for n(Brown) and 50 for Total

`P(Brown) = (20)/(50)`

Calculating P(Green)

`P(Green) = (n(Green))/(Total)`

Substitute 6 for n(Green) and 50 for Total

`P(Green) = (6)/(50)`

So;

`P(Brown\ or\ Green) = P(Brown) + P(Green)`

`P(Brown\ or\ Green) = (20)/(50) + (6)/(20)`

Take LCM

`P(Brown\ or\ Green) = (20+6)/(50)`

`P(Brown\ or\ Green) = (26)/(50)`

Divide the numerator and denominator by 2

`P(Brown\ or\ Green) = (13)/(25)`