Question

12.

Find the values in the interval [-n/2, n] that satisfy the equation.
arctan (V3/3) = x
с
a. since tan (n/6) = 13/3, X = n/6
b. since sin (-1/4)= -V2/2, x = -1/4
c. since cos (3n/2) = -1/2, X = 3n/2
d. since cos 0 = 1, x = 0
e. since cos (1/4) = V2/2, X = n/4
13

Answer 1

Explanation:

`tan^(-1) ((√(3) )/(3) )=x\\tan x=(√(3) )/(3) =tan ((\pi)/(6) )\\x=(\pi)/(6)`