Question

3x to the 2nd power +4y to the 2nd power x=2 y=1 z=-3

Answer 1

`\huge\boxed{16}`

Explanation:

`3x^2+4y^2\ \text{for}\ x=2;\ y=1.\\\\\text{Substitute:}\\\\3(2)^2+4(1)^2=3(4)+4(1)=12+4=16\\\\\text{Used PEMDAS}`

Answer 2

Explanation:

3(2)^2 + 4(1)^2

3(4) + 4

12+4= 16