Question

Pls help me for question no.4

Answer 1

Area of the composite figure = 75.25 cm²

Explanation:

Question (4). Given figure is a composite figure having,

(1). Right triangle STU

(2). A kite PSUV

(3). A trapezoid PQRS

Now we will calculate the area of each figure.

(1). Area of the right triangle =
`(1)/(2)(\text{ST})(\text{TU})`

=
`(1)/(2)(3.5)(3)`

= 5.25 cm²

(2). Area of the kite PSUV =
`(1)/(2)(\text{Diagonal 1})(\text{Diagonal 2})`

=
`(1)/(2)(\text{PU})(\text{SV})`

=
`(1)/(2)(\text{TS+RQ})(\text{SV})`

=
`(1)/(2)(3.5+7)(6)` [Since SV = 2 × 3 = 6 cm]

=
`3* 10.5`

= 31.5 cm²

(3). Area of the trapezium =
`(1)/(2)(b_1+b_2)(h)` [Where
`b_1` and
`b_2` are the bases and h is the distance between the bases]

=
`(1)/(2)[(7-3)+7](7)`

=
`(77)/(2)`

= 38.5 cm²

Total area of the given figure = 5.25 + 31.5 + 38.5

= 75.25 cm²