Question

A sodium chloride solution with a Molarity of 0.239 M has a volume of 158 mL. How many grams

of solute are in the solution?

Answer 1

2.21 grams

Step-by-step explanation:

The first thing you need to do is find the chemical formula for sodium chloride which is NaCl (Molar mass: 58.44 g/mol).

The next the thing to do is to convert the mL to L by dividing by 1000 which will give us 0.158 L.

Now we look at the molarity formula M = n/L, plug in the molarity for M and the liters for L. 0.239 M (mol/L) = n/0.158 L.

Solve for n to get the number of moles of NaCl in the solution. You should get 0.037762 moles.

Then we have to multiply this by the molar mass of NaCl, (0.037762 mol)*(58.44 g/mol).

Moles cancel and when we round to sig figs we are left with 2.21 grams.

Hope this helps.