Question

Two moles of neon gas enclosed in a constant volume system receive 4250 J of heat. If the gas was initially at 293 K, what is the final temperature of the neon

Answer 1

=355.5K

Step-by-step explanation:

Specific heat, Q = mcΔT

where

• Q= 4250J
• ΔT= change in temp = final temp - initial temp
• c = specific heat capacity = 1.7
• m = mass of substance in grams

[1 mole of Ne = 20g; 2 moles of Ne = 2 × 20 = 40g]

4250 = 40 × 1.7 × (final - 293K)

final - 293k = 4250 / ( 40 × 1.7)

Final temp = 62.5 + 293

=355.5K

I hope this steps are simple to follow and understand.