Question

g When a thin-filament light bulb is connected to two 1.6 V batteries in series, the current is 0.075 A. What is the resistance of the glowing thin-filament bulb

Answer 1

R = 42.67 ohms

Step-by-step explanation:

It is given that, a thin-filament light bulb is connected to two 1.6 V batteries in series, the current is 0.075 A.

It means that when two batteries are connected in series, then the total voltage is 3.2 volts

Let R is the resistance of the glowing thin-filament bulb. So, using Ohm's law we get :

`V=IR\\\\R=(V)/(I)`

So,

`R=(3.2)/(0.075)\\\\R=42.67\ \Omega`

So, the resistance of the bulb is 42.67 ohms.