Answer:
See Explanation below
Explanation:
This question has missing details because the number of video games is not stated;
However, you'll arrive at your answer if you follow the steps I'll highlight;
The question requests for the number of arrangement; That means we're dealing with permutation
Let's assume the number of video games is n;
To arrange n games, we make use of the following permutation formula;
![^nP_n = (n!)/((n-n)!)](https://img.qammunity.org/2021/formulas/mathematics/college/4rga6n4dnucqs36six3piiobukf33x3dtb.png)
Simplify the denominator
![^nP_n = (n!)/(0!)](https://img.qammunity.org/2021/formulas/mathematics/college/5bqaz7qvp5ek5pqaljkrkmkcvu042f1w2v.png)
0! = 1; So, we have
![^nP_n = (n!)/(1)](https://img.qammunity.org/2021/formulas/mathematics/college/jxrf0b9p20j2uypf8s6wqrjx0c1cwvygac.png)
![^nP_n = n!](https://img.qammunity.org/2021/formulas/mathematics/college/agzbjyo57wkp5jwlhyc5qzlqrg5x3btce4.png)
Now, let's assume there are 3 video games;
This means that n = 3
![^3P_3 = 3!](https://img.qammunity.org/2021/formulas/mathematics/college/ls2cxobdzkxng9szafjxhpo2szu09p3gsf.png)
![^3P_3 = 3 * 2 * 1](https://img.qammunity.org/2021/formulas/mathematics/college/1m5vwdovj5ru9miiurvbq8g86svbc56nkl.png)
![^3P_3 = 6\ ways](https://img.qammunity.org/2021/formulas/mathematics/college/9afrq6p2yg9ttyhmd4f1724261a10pk84y.png)
So, whatever the number of video games is; all you have to do is; substitute this value for n;