Answer:
B.
![(7x^2 + 11x)/(x^2 + 6x + 5)](https://img.qammunity.org/2021/formulas/mathematics/college/7gxmwt88x40j8jop3lsyohjeo5ew5mnxjy.png)
Explanation:
The sum is worked as shown below:
![(x)/(x + 1) + (6x)/(x + 5)](https://img.qammunity.org/2021/formulas/mathematics/college/3waebd0kq2a81damzf6cva4q0sk4kt66me.png)
Use the common denominator to divide each denominator, then use the result to multiply the numerator, you'd have the following:
![(x(x + 5) + 6x(x + 1))/((x + 1)(x + 5))](https://img.qammunity.org/2021/formulas/mathematics/college/hevxg3ylxgtzgyz4u49bugl8vz25kdxxhm.png)
Use the distributive property of multiplication to solve
![(x(x) + x(5) + 6x(x) + 6x(1))/((x(x + 5) + 1(x + 5))](https://img.qammunity.org/2021/formulas/mathematics/college/1glatfr46t0y25swiv3qwmf6ol7jmguyxk.png)
![(x^2 + 5x + 6x^2 + 6x)/(x^2 + 5x + x + 5)](https://img.qammunity.org/2021/formulas/mathematics/college/btzfdafc5l4bb1a4gezmjhkdi47yztozf8.png)
Pair like terms
![(x^2 + 6x^2 + 5x + 6x)/(x^2 + 6x + 5)](https://img.qammunity.org/2021/formulas/mathematics/college/hydhga6o331gugn2js31qsh5rkyy02pfh5.png)
![(7x^2 + 11x)/(x^2 + 6x + 5)](https://img.qammunity.org/2021/formulas/mathematics/college/7gxmwt88x40j8jop3lsyohjeo5ew5mnxjy.png)
The answer is B.