Question

How do you solve these problems?

Answer 1

Explanation:

Hello,

a. The area of region P is the area of the rectangle 1 * e minus the

`\displaystyle \int\limits^0_1 {e^x} \, dx=[e^x]^(1)_(0)=e-1`

So this is e - (e-1) = e - e + 1 = 1

b. The area of region P is the area of the rectangle 1 * e minus P and minus the

`\displaystyle \int\limits^0_1 {e^(-x)} \, dx=[-e^(-x)]^(1)_(0)=-e^(-1)+1`

So this is

`e - 1 - (-e^(-1)+1) = e-1+e^(-1)-1=e+e^(-1)-2`

This is around 1.08616127...

Hope this helps.

Do not hesitate if you need further explanation.

Thank you