Final answer:
The case of five babies with a chance of recovery from an ailment is an example of a binomial experiment. There are five trials (n=5), a constant success probability (p=0.3), and a constant failure probability (q=0.7). The random variable x can take values from 0 to 5, corresponding to the number of babies recovering.
Step-by-step explanation:
The scenario described involves a hospital caring for five babies born with a certain ailment, where about 30% of such babies recover fully. The experiment in question appears to be a binomial experiment since it fulfills certain criteria:
Fixed number of trials (n): There are five babies; hence, there are five trials. Therefore, n=5.
Two possible outcomes (Success and Failure): Either a baby recovers fully (Success) or does not (Failure).
Probability of success (p) remains constant: The probability of a baby recovering is 30% or 0.3 for each baby, so p=0.3.
Probability of failure (q): The probability that a baby does not recover is q=1-p, which equals 1-0.3=0.7.
The possible values of the random variable x, which represents the number of babies that recover fully, are 0, 1, 2, 3, 4, or 5. These are all the outcomes possible within five trials.