3.4k views
1 vote
Help me please I need answers

Help me please I need answers-example-1
User Pennersr
by
9.1k points

1 Answer

1 vote

Answer:

The solution of the system of equations are;

(-2, -6) and (4, 6)

Explanation:

-2·x + y = -2...............(1)


y = -(1)/(2) \cdot x^2 + 3 \cdot x + 2........(2)

Equation (1) gives;

y = 2·x - 2

From which we have;


2 \cdot x - 2 = -(1)/(2) \cdot x^2 + 3 \cdot x + 2


0= -(1)/(2) \cdot x^2 + x + 4

x² -2·x -8 = 0

(x - 4)·(x + 2) = 0

x = 4 or x = -2

The y-coordinate values are;

y = 2×(-2) - 2 = -6 and y = 2×(4) - 2 = 6

The solution points are;

(-2, -6) and (4, 6).

The points where the equation, -2·x + y = -2 and the equation
y = -(1)/(2) \cdot x^2 + 3 \cdot x + 2 intersect are (-2, -6) and (4, 6).

Help me please I need answers-example-1
User Denis Michealk
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories