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What is the equation of the line that passes through (1, 3) and (-2, -3)? y = -2x + 1 y = 2x + 1 y = x - 1 y = -x + 1

2 Answers

5 votes

Answer:


\boxed{y = 2x + 1}

Explanation:

The line passes through (1, 3).

The solution of the line is the points it crosses.

x = 1

y = 3

Plug x as 1 and y as 3 in the equation.

y = -2x + 1

3 = -2(1) + 1

3 = -2 + 1

3 = -1 False

Plug x as 1 and y as 3 in the equation.

y = 2x + 1

3 = 2(1) + 1

3 = 2 + 1

3 = 3 True

Plug x as 1 and y as 3 in the equation.

y = x - 1

3 = 1 - 1

3 = 0 False

Plug x as 1 and y as 3 in the equation.

y = -x + 1

3 = -(1) + 1

3 = -1 + 1

3 = 0 False

User Deividi Silva
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5.8k points
1 vote

Answer: y = 2x+1

Explanation:

It is the only line with (1,3) as a solution. A slower algebraic way to solve this would be to plug in 1 for x and 3 for y, then, out of the equations in which it works, plug in -2 for x and -3 for y. The equation that remains true for both points is the answer.

Hope it helps <3

What is the equation of the line that passes through (1, 3) and (-2, -3)? y = -2x-example-1
User Ogre
by
5.6k points