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Graph the equation y = -x2 + 5x + 24. How do the values of x = 8 and x = -3 on the graph relate to this situation? Find the width of the archway.

User Chu Yeow
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1 Answer

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Answer:

The values of x = 8 and x = -3 are the x-intercepts of this equation. The width of the archway is 11 units.

Explanation:

Let be
y = -x^(2)+5\cdot x +24, which is now graphed with the help of a graphing tool, the outcome is included below as attachment. The values of x = 8 and x = -3 are the x-intercepts of this equation, that is, values of x such that y is equal to zero. Algebraically speaking, both are roots of the second-order polynomial.

The width of the archway (
d) is the distance between both intercepts, which is obtained by the following calculation:


d = |x_(1)-x_(2)|, where
x_(1) \geq x_(2).

If
x_(1) = 8 and
x_(2) = -3, then:


d = |8-(-3)|


d = 8 +3


d = 11

The width of the archway is 11 units.

Graph the equation y = -x2 + 5x + 24. How do the values of x = 8 and x = -3 on the-example-1
User Joshua Hyatt
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