Question

Determine the zeros of r=2sin5theta

Answer 1

θ = 0, pi/5, 2pi/5, 3pi/5, 4pi/5 ,pi

Explanation:

Answer 2

`\theta=(n\pi)/(5)`

Explanation:

You have the following function:

`r=2sin5\theta` (1)

In order to find the zeros of the function you equal to zero the equation (1), and then you solve for θ:

`2sin5\theta=0\\\\sin5\theta=0\\\\5\theta=sin^(-1)(0)=n\pi;\ \ \ \ n=0,1,2,3,..\\\\\theta=(n\pi)/(5)`

Then, there are infinite zeros for the function of the equation (1), because n has infinite positive integers values.