Answer:
-12p^7q^9
Explanation
-\left(-\frac{2}{3}pq^4\right)^2\cdot \:27p^5q
-27\cdot \frac{2^2p^2q^8}{3^2}p^5q
Multiply the fractions
\frac{2^2p^2q^8\cdot \:27p^5q}{3^2}
-\frac{2^2\cdot \:27p^7q^9}{3^2}
-2^2\cdot \:3p^7q^9
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